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Questions - stringi

Dynamically generate subset column names for a dataframe using for loop

For the following dataframe df: df <- structure(list(id = c("M0000607", "M0000609", "M0000612"), `2021-08(actual)` = c(12.6, 19.2, 8.3), `2021-09(actual)` = c(10.3, 1...
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ah bon

r

vector

dplyr

stringi

Votes: 0

Answers: 1

Latest Answer

You can do it in base R like this with a bit of help from the lubridate package. year_months <- c('2021-12', '2021-11', '2021-10') curr <- lubridate::ym(year_months) prev <- curr - months(2...
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ekoam

r remove keywords in a column

I have a column in my dataframe with words like this. ColA 2-4 Model Group1 Group ACH Group2 Phenols Group1 Group ACH Group2 MONO MHPP Group1 Group ACH Group2 I want to create two additional columns ...
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Ahir Bhairav Orai

r

gsub

stringi

string-substitution

Votes: 0

Answers: 3

Latest Answer

Here is another option using tidyverse. First, I create a new column (ColB) using str_remove to remove any of the keywords. Then, I use str_extract_all to pull out only the keywords to create another...
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AndrewGB

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