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Questions - tkinter-entry

Why tkinter multiple window GUI not working properly?

I am creating multiple window GUI using tkinter. I did not receive any errors. First window runs successfully but when I clicked the button the second window doesn't run. I don't understand where ther...
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Abhishek Gupta

python

tkinter

tkinter-canvas

tkinter-entry

Votes: 0

Answers: 1

Latest Answer

command=lambda: controller.show_frame(SecondWindow), is passing the class id as argument so page_name is not being found. suggest command=lambda: controller.show_frame('SecondWindow')
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InhirCode

Remove whole Entry row (5 boxes) in tkinter

I have button and a function which creates 5 Entry boxes in newline every time you click it def __init__(self, master): [...] self.rows_list = 2 self.new_button = ttk.Button(self.tab1, tex...
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gipcu

python

tkinter

tkinter-entry

Votes: 0

Answers: 1

Latest Answer

For your case, since you have self.row_list to be used as the next row that those new entries be created, you can use this variable to get the widgets in the last row and destroy them: def __init_...
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acw1668

How to read the text below the mouse when clicking on a tkinter Text widget and paste it in an Entry widget?

I am writing a program that pulls data from a server. Initially, the program asks the server to print the data available for a specific day. The output on the Text widget is shown in the for loop: def...
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AndreaPython

python

tkinter

mouseevent

tkinter-entry

tkinter-text

Votes: 0

Answers: 1

Latest Answer

You can use: tex1.get('insert linestart', 'insert lineend') to get the ID where the input cursor is. However since you bind on <Button-1>, the input cursor is not updated when the callback is ...
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acw1668

How to check the type of tkinter-widget-objects

I wanna create a simple GUI for a research project. For this I have plenty of widgets and I want to check what their type is. Lets take the entry-widget as an example. I have entries, which look like ...
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Tybald

python

if-statement

tkinter

tkinter-entry

Votes: 0

Answers: 1

Latest Answer

Use isinstance: if isinstance(current_widget, tk.Entry): ... Or if widget_type == 'tkinter.Entry': ... I prefer the first solution.
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Corralien

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